Equation of plane
Equation of Plane
In three-dimensional space, a plane can be defined as a flat, two-dimensional surface that extends infinitely in all directions. The equation of a plane is a mathematical representation that describes all the points (x, y, z) that lie on the plane.
Vector Form of the Equation of a Plane
A plane can be defined using a point and a normal vector. The normal vector is perpendicular to the plane. If we have a point $P_0(x_0, y_0, z_0)$ and a normal vector $\vec{n} = (a, b, c)$, then the vector form of the equation of a plane is given by:
$$ \vec{n} \cdot (\vec{r} - \vec{r_0}) = 0 $$
where $\vec{r} = (x, y, z)$ is the position vector of any point on the plane, and $\vec{r_0} = (x_0, y_0, z_0)$ is the position vector of the given point $P_0$.
Expanding the dot product, we get:
$$ a(x - x_0) + b(y - y_0) + c(z - z_0) = 0 $$
Scalar (Cartesian) Form of the Equation of a Plane
The scalar form of the equation of a plane is derived from the vector form and is written as:
$$ ax + by + cz + d = 0 $$
where $a$, $b$, and $c$ are the components of the normal vector $\vec{n}$, and $d$ is a scalar constant. The value of $d$ can be found by substituting the coordinates of the given point $P_0$ into the equation:
$$ d = - (ax_0 + by_0 + cz_0) $$
General Form of the Equation of a Plane
The general form of the equation of a plane is similar to the scalar form and is usually written as:
$$ Ax + By + Cz + D = 0 $$
where $A$, $B$, $C$ are the coefficients that correspond to the normal vector, and $D$ is the constant term.
Table of Differences and Important Points
Property | Vector Form | Scalar Form | General Form |
---|---|---|---|
Definition | Defined using a point and a normal vector | Derived from the vector form | Similar to scalar form, often used for simplicity |
Equation | $\vec{n} \cdot (\vec{r} - \vec{r_0}) = 0$ | $ax + by + cz + d = 0$ | $Ax + By + Cz + D = 0$ |
Normal Vector | Explicitly used | Coefficients $a$, $b$, $c$ represent the normal vector | Coefficients $A$, $B$, $C$ represent the normal vector |
Given Point | Required to find the equation | Used to find the constant $d$ | Not explicitly used in the equation |
Constant Term | Not present in vector form | $d = - (ax_0 + by_0 + cz_0)$ | $D$ is the constant term |
Examples
Example 1: Finding the Equation of a Plane
Given a point $P_0(1, -2, 3)$ and a normal vector $\vec{n} = (4, -5, 6)$, find the equation of the plane.
Solution:
Using the vector form, we have:
$$ 4(x - 1) - 5(y + 2) + 6(z - 3) = 0 $$
Expanding and simplifying, we get the scalar form:
$$ 4x - 5y + 6z - 23 = 0 $$
Example 2: Determining if a Point Lies on a Plane
Determine if the point $Q(2, -1, 4)$ lies on the plane $2x - 3y + z - 6 = 0$.
Solution:
Substitute the coordinates of point $Q$ into the equation of the plane:
$$ 2(2) - 3(-1) + 1(4) - 6 = 4 + 3 + 4 - 6 = 5 $$
Since the result is not zero, point $Q$ does not lie on the plane.
Understanding the equation of a plane is crucial for solving problems in three-dimensional geometry, such as finding the intersection of planes, distances from points to planes, and angles between planes.