Auxiliary circle


Auxiliary Circle

The concept of an auxiliary circle is commonly associated with the study of ellipses in mathematics. It is a useful tool for understanding the properties of an ellipse and for solving problems related to ellipses.

Definition

An auxiliary circle of an ellipse is a circle that has the same center as the ellipse and whose diameter is equal to the major axis of the ellipse.

For an ellipse with the equation $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$, where $a$ is the semi-major axis and $b$ is the semi-minor axis, the auxiliary circle has the equation $x^2 + y^2 = a^2$.

Properties

  • The auxiliary circle and the ellipse share the same center.
  • The diameter of the auxiliary circle is equal to the length of the major axis of the ellipse.
  • The auxiliary circle is used to define the parametric equations of the ellipse.

Parametric Equations

Using the auxiliary circle, we can derive the parametric equations of the ellipse. If $(a \cos t, a \sin t)$ represents a point on the auxiliary circle, then the corresponding point on the ellipse is given by $(a \cos t, b \sin t)$.

The parametric equations of the ellipse are:

$$ \begin{align} x &= a \cos t \ y &= b \sin t \end{align} $$

where $t$ is the parameter, varying from $0$ to $2\pi$.

Table of Differences and Important Points

Feature Ellipse Auxiliary Circle
Equation $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$ $x^2 + y^2 = a^2$
Center Same as ellipse Same as ellipse
Radius Not applicable (semi-major and semi-minor axes) $a$ (equal to the semi-major axis of the ellipse)
Parametric Equations $x = a \cos t$, $y = b \sin t$ $x = a \cos t$, $y = a \sin t$
Use Describes an ellipse Helps derive the parametric equations of the ellipse

Examples

Example 1: Finding Points on an Ellipse

Given an ellipse with the equation $\frac{x^2}{9} + \frac{y^2}{4} = 1$, find the points on the ellipse corresponding to the parameter $t = \frac{\pi}{6}$.

Solution:

The semi-major axis $a = 3$ and the semi-minor axis $b = 2$. Using the parametric equations:

$$ \begin{align} x &= a \cos t = 3 \cos \left(\frac{\pi}{6}\right) = 3 \cdot \frac{\sqrt{3}}{2} = \frac{3\sqrt{3}}{2} \ y &= b \sin t = 2 \sin \left(\frac{\pi}{6}\right) = 2 \cdot \frac{1}{2} = 1 \end{align} $$

The point on the ellipse is $\left(\frac{3\sqrt{3}}{2}, 1\right)$.

Example 2: Using the Auxiliary Circle

Given the same ellipse as in Example 1, find the corresponding point on the auxiliary circle for $t = \frac{\pi}{6}$.

Solution:

The radius of the auxiliary circle is equal to the semi-major axis $a = 3$. Using the parametric equations for the circle:

$$ \begin{align} x &= a \cos t = 3 \cos \left(\frac{\pi}{6}\right) = 3 \cdot \frac{\sqrt{3}}{2} = \frac{3\sqrt{3}}{2} \ y &= a \sin t = 3 \sin \left(\frac{\pi}{6}\right) = 3 \cdot \frac{1}{2} = \frac{3}{2} \end{align} $$

The point on the auxiliary circle is $\left(\frac{3\sqrt{3}}{2}, \frac{3}{2}\right)$.

In conclusion, the auxiliary circle is a powerful concept that simplifies the study of ellipses, particularly when dealing with parametric equations and trigonometric relationships. It provides a circular reference that makes it easier to understand the elliptical shape and its geometric properties.