Condition on equation of second degree to represent circle
Condition on Equation of Second Degree to Represent Circle
A general second-degree equation in two variables x and y can represent various conic sections, such as circles, ellipses, parabolas, or hyperbolas, depending on the conditions it satisfies. To specifically represent a circle, certain conditions must be met.
General Second-Degree Equation
The general form of a second-degree equation is:
$$ Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 $$
Where A, B, C, D, E, and F are constants.
Circle Equation
A circle with center at $(h, k)$ and radius $r$ is represented by the equation:
$$ (x - h)^2 + (y - k)^2 = r^2 $$
Expanding this equation, we get:
$$ x^2 - 2hx + h^2 + y^2 - 2ky + k^2 - r^2 = 0 $$
Which simplifies to:
$$ x^2 + y^2 - 2hx - 2ky + (h^2 + k^2 - r^2) = 0 $$
Comparing this with the general second-degree equation, we can see that for a second-degree equation to represent a circle, it must satisfy certain conditions.
Conditions for a Second-Degree Equation to Represent a Circle
Here are the conditions that must be met:
- The coefficients of $x^2$ and $y^2$ must be equal and non-zero (i.e., $A = C \neq 0$).
- The coefficient of the $xy$ term must be zero (i.e., $B = 0$).
- The equation must not represent a degenerate conic (i.e., it should not represent a point or a line).
Table of Differences and Important Points
Property | General Second-Degree Equation | Circle Equation |
---|---|---|
Coefficients of $x^2$ and $y^2$ | May differ (A and C) | Must be equal and non-zero |
Coefficient of $xy$ | Can be non-zero (B) | Must be zero |
Center | Not defined | $(h, k)$ |
Radius | Not defined | $r$ |
Degenerate Cases | May represent a point or line | Must represent a proper circle |
Examples
Example 1: Identifying a Circle
Consider the equation:
$$ 2x^2 + 2y^2 - 8x + 4y + 4 = 0 $$
Let's check if it represents a circle:
- Coefficients of $x^2$ and $y^2$: Both are 2 (equal and non-zero).
- Coefficient of $xy$: There is no $xy$ term, so $B = 0$.
- It does not represent a degenerate conic.
Since all conditions are met, this equation represents a circle.
Example 2: Not a Circle
Now consider the equation:
$$ x^2 + 2xy + y^2 + 3x + 4y + 5 = 0 $$
Checking the conditions:
- Coefficients of $x^2$ and $y^2$: Both are 1 (equal and non-zero).
- Coefficient of $xy$: It is 2, which is non-zero, so $B \neq 0$.
Since the coefficient of $xy$ is non-zero, this equation does not represent a circle.
Conclusion
For a second-degree equation to represent a circle, it must satisfy specific conditions regarding the coefficients of $x^2$, $y^2$, and $xy$. By comparing the given equation with the standard form of a circle's equation, one can determine whether it represents a circle or not. Understanding these conditions is crucial for solving problems related to circles in exams.