Design a combinational logic circuit with 4 inputs A, B, C, D. The output Y goes high if and only if A and C are high. Draw the truth table, minimize the boolean function using K-map, draw the circuit diagram.
Q.) Design a combinational logic circuit with 4 inputs A, B, C, D. The output Y goes high if and only if A and C are high. Draw the truth table, minimize the boolean function using K-map, draw the circuit diagram.
Subject: Digital SystemsAnswer:
Step 1: Truth Table
The first step in designing a combinational logic circuit is to define the problem in terms of the inputs and the required output. This is usually done using a truth table. For the given problem, the truth table would look like this:
A | B | C | D | Y |
---|---|---|---|---|
0 | 0 | 0 | 0 | 0 |
0 | 0 | 0 | 1 | 0 |
0 | 0 | 1 | 0 | 0 |
0 | 0 | 1 | 1 | 0 |
0 | 1 | 0 | 0 | 0 |
0 | 1 | 0 | 1 | 0 |
0 | 1 | 1 | 0 | 0 |
0 | 1 | 1 | 1 | 0 |
1 | 0 | 0 | 0 | 0 |
1 | 0 | 0 | 1 | 0 |
1 | 0 | 1 | 0 | 1 |
1 | 0 | 1 | 1 | 1 |
1 | 1 | 0 | 0 | 0 |
1 | 1 | 0 | 1 | 0 |
1 | 1 | 1 | 0 | 1 |
1 | 1 | 1 | 1 | 1 |
From the truth table, we can see that the output Y is high (1) only when both A and C are high (1), regardless of the values of B and D.
Step 2: Karnaugh Map (K-Map)
The next step is to minimize the boolean function using a Karnaugh map (K-map). A K-map is a graphical representation of a logic function’s truth table. It is used to simplify the boolean function.
For a 4-variable K-map, the map is a 4x4 grid, with the rows representing the combinations of A and B, and the columns representing the combinations of C and D. The cells are filled with the corresponding output Y from the truth table.
The K-map for the given problem would look like this:
00 | 01 | 11 | 10 | |
---|---|---|---|---|
00 | 0 | 0 | 0 | 0 |
01 | 0 | 0 | 0 | 0 |
11 | 0 | 0 | 1 | 1 |
10 | 0 | 0 | 1 | 1 |
From the K-map, we can see that the minimized boolean function is Y = AC.
Step 3: Circuit Diagram
The final step is to draw the circuit diagram. The circuit diagram for the minimized boolean function Y = AC is quite simple. It consists of two inputs A and C connected to an AND gate, with the output of the AND gate being the output Y.
Here is a simple representation of the circuit diagram:
A ------
|
AND ---- Y
|
C ------
In this circuit, the output Y will be high (1) only when both A and C are high (1), which is exactly the behavior defined in the problem statement.