Design a combinational logic circuit with inputs A, B, C, D. The output Y goes high only if A and C are high. Draw the truth table and Boolean function using K-map. Draw the circuit diagram.
Q.) Design a combinational logic circuit with inputs A, B, C, D. The output Y goes high only if A and C are high. Draw the truth table and Boolean function using K-map. Draw the circuit diagram.
Subject: Digital SystemsAnswer:
The first step in designing a combinational logic circuit is to define the problem. In this case, the output Y should go high only if inputs A and C are high, regardless of the states of B and D.
The next step is to create a truth table that represents this logic. The truth table for this logic would look like this:
A | B | C | D | Y |
---|---|---|---|---|
0 | 0 | 0 | 0 | 0 |
0 | 0 | 0 | 1 | 0 |
0 | 0 | 1 | 0 | 0 |
0 | 0 | 1 | 1 | 0 |
0 | 1 | 0 | 0 | 0 |
0 | 1 | 0 | 1 | 0 |
0 | 1 | 1 | 0 | 0 |
0 | 1 | 1 | 1 | 0 |
1 | 0 | 0 | 0 | 0 |
1 | 0 | 0 | 1 | 0 |
1 | 0 | 1 | 0 | 1 |
1 | 0 | 1 | 1 | 1 |
1 | 1 | 0 | 0 | 0 |
1 | 1 | 0 | 1 | 0 |
1 | 1 | 1 | 0 | 1 |
1 | 1 | 1 | 1 | 1 |
From the truth table, we can derive the Boolean function using Karnaugh map (K-map) simplification.
The K-map for this function would look like this:
1 | 1 | |||
1 | 1 | |||
0 | 0 | |||
0 | 0 |
From the K-map, we can see that the simplified Boolean function for the output Y is:
Y = A.C
This means that the output Y is high (1) only when both A and C are high (1).
The final step is to draw the circuit diagram. The circuit diagram for this function would consist of two inputs A and C connected to an AND gate, with the output Y connected to the output of the AND gate.
Here is a simple representation of the circuit diagram:
A ----\
AND ----> Y
C ----/
In this circuit diagram, the AND gate represents the Boolean function Y = A.C. The inputs A and C are connected to the inputs of the AND gate, and the output Y is connected to the output of the AND gate. When both A and C are high (1), the output Y goes high (1). Otherwise, the output Y stays low (0).